Class 10 Mirror and Lens Sign Conventions Compared

Most sign errors begin before substitution. Sketch the optical device, put the object on the left with light travelling right, and choose the origin at the mirror pole or lens optical centre.

Sources checked 2 October 2026 · original study guide · CBSE/NCERT context

Comparison guide · Read at your own pace

Compare the rules

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QuantitySpherical mirrorThin lens
Formula1/f = 1/v + 1/u1/f = 1/v − 1/u
Magnificationm = −v/um = v/u
Usual real object on the leftu is negativeu is negative
Converging device in airConcave mirror: f negativeConvex lens: f positive

Read the labelled model

Concave mirror: object 36 cm left, focal length −12 cm, real inverted half-height image 18 cm left. The horizontal ray travels back through the focus after reflection; the other ray reflects at the pole. Original paraxial construction.FObjectImagePole: origin
Concave mirror: object 36 cm left, focal length −12 cm, real inverted half-height image 18 cm left. The horizontal ray travels back through the focus after reflection; the other ray reflects at the pole. Original paraxial construction.
Convex lens: object 36 cm left, focal length +12 cm, real inverted half-height image 18 cm right. The horizontal ray travels through the far focus after refraction; the other ray passes through the optical centre. Original paraxial construction.FObjectImageOptical centre: origin
Convex lens: object 36 cm left, focal length +12 cm, real inverted half-height image 18 cm right. The horizontal ray travels through the far focus after refraction; the other ray passes through the optical centre. Original paraxial construction.

Assign signs from directions

Distances measured in the direction of incident light are positive; those measured oppositely are negative. Heights above the principal axis are positive and those below it negative. These are directed quantities. Do not decide that every real image must have a positive image distance.

A concave mirror forming a real image places it on the object side, giving negative v in this arrangement. A convex lens forming a real image places it on the opposite side, giving positive v. Both images can be inverted.

Compare two original calculations

For a concave mirror with f = −12 cm and u = −36 cm, 1/v = −1/12 + 1/36 = −1/18. Thus v = −18 cm and m = −(−18)/(−36) = −0.5. The image is real, inverted and half the object height.

For a convex lens with f = +12 cm and u = −36 cm, 1/v = 1/12 − 1/36 = 1/18. Hence v = +18 cm and m = 18/(−36) = −0.5. The size and orientation agree, but the image lies on the other side of the lens.

A final three-part check

State position, orientation and relative size separately. Negative magnification signals inversion; its magnitude gives the size ratio. If your sketch shows a real image on the opposite side of a mirror, revisit the physical setup before changing signs to force an answer.

Choose what to study next

Sources and scope

This is a focused learning resource, not a complete chapter or a prediction of board questions. Use your current syllabus and the paper-specific marking scheme for assessment requirements.

Try a short check, then return to the explanation

Optional TutorMax original practice: five questions on light, lenses and mirrors, with explanations and a fresh retest. These checks sample a few skills; they are not official paper questions or a whole-subject readiness score. Existing explanations and official paper downloads stay available on this page.

Frequently asked questions

Does negative magnification mean a smaller image?

No. Its sign describes orientation. Magnitude below one means smaller; magnitude above one means larger.

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